2x^2=18-12x

Solution for 2x^2=18-12x equation:

2x^2=18-12x

We move all terms to the left:

2x^2-(18-12x)=0

We add all the numbers together, and all the variables

2x^2-(-12x+18)=0

We get rid of parentheses

2x^2+12x-18=0

a = 2; b = 12; c = -18;
Δ = b2-4ac
Δ = 122-4·2·(-18)
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{2}}{2*2}=\frac{-12-12\sqrt{2}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{2}}{2*2}=\frac{-12+12\sqrt{2}}{4}
$